(2/3)^4x+9=(27/8)^x

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Solution for (2/3)^4x+9=(27/8)^x equation: 



(2/3)^4x+9=(27/8)^x

We move all terms to the left:

(2/3)^4x+9-((27/8)^x)=0



Domain of the equation: 3)^4x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 8)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)^4x-((+27/8)^x)+9=0

We calculate fractions


16^x)/3^4x*8)^x))+(-81^4x/3^4x*8)^x))+9=0

We can not solve this equation

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